python - Converting an if/else block with True/False statements into a dictionary -

i iterating through characters in string, , want determine type of each character.

this can done if/else block:

    if char.isdigit():         char_type = 'number'     elif char.isalpha():         char_type = 'letter'     elif char in {'*', '/', '+', '-', '='}:         char_type = 'operator'     else:         char_type = 'other' 

if code this:

    if val == 1:         char_type = 'number'     elif val == 2:         char_type = 'letter'     elif val == 3:         char_type = 'operator' 

the dictionary be:

d = {1: 'number', 2: 'letter', 3: 'operator'} 

but in case, each of statements either true or false. can converted dictionary?

yes, can use d[char] syntax, hardly sees worth cost in complexity , readability.

you encapsulate if/else in __getitem__ method of class, , use [] syntax retrieve character type, so:

class chartype:     def __getitem__(self, char):         if char.isdigit():             char_type = 'number'         elif char.isalpha():             char_type = 'letter'         elif char in {'*', '/', '+', '-', '='}:             char_type = 'operator'         else:             char_type = 'other'         return char_type  d = chartype()  print(d["a"], d["+"])