Pass parameter to function if passed by user python -

this 1 should simple. have function , call function package within function. want customize passing arguments package of function on whether user has passed arguments function. example code:

import somepackage sp  def myfunc(foo, bar, baz=none, xad=false):     # code stuff...     # finally:     if baz not none:         sp.somefunc(data=foo, method=bar, aux=baz)     else:         sp.somefunc(data=foo, method=bar) 

is there way replace last 4 lines 1 neat pythonic line? like:

def myfunc(foo, bar, baz=none, xad=false):     # code stuff...     # finally:     sp.somefunc(data=foo, method=bar, [aux=baz if baz not none]) 

you can use argument unpacking this:

def func1(one, two, three):     args = {"one": one, "two": two, "three": three}     func2(*args)  def func2(one, two, three):     print "one = %s, 2 = %s, 3 = %s" % (one, two, three)  if __name__ == "__main__":     func1(one="does", two="this", three="work") 

example run:

python foo.py 1 = does, 2 = this, 3 = work 

you can of course modify args see fit before passing on.