python - finding repeat characters in a list for Hangman-python3 -

for hangman application code followed;

text=list(input("enter word guessed:")) guess=[] tries=5 clue=input("enter clue: ") print('rules:\n 1) type exit exit applcation \n 2) type ? clue')  in range(len(text)):     t='_ '     guess.append(t) print(guess)  while true:     g=input("guess letter: ")     if g in text:         print("you guessed correct")         y=text.index(g)         guess[y]=g         print(guess)     continue elif g=='exit':     exit() elif g=='?':     print(clue) elif tries==0:     print ("you have run out of tries, bye bye")     exit() else:     print(g,' not in word')     tries -=1     print("you have",tries,'tries left')     continue 

for code instance if text guessed 'avatar', when 'a' guessed, return first instance of letter , not positions; text[2][4]

your issue comes using y = text.index(g). return index of first match finds. need more akin following:

if g in text:     print("you guessed correct")     y in range(len(text)):         if text[y] == g:             guess[y] = g     print(guess)