python - Multiply an integer in a list by a word in the list -

i'm not sure how multiply number following string string. want find rmm of compound started making dictionary of rmms have them added together. issue compounds such h2o.

name = input("insert name of molecule/atom find rmm/ram: ") compound = re.sub('([a-z])', r' \1', name) compound = compound.split(' ') r = re.split('(\d+)', compound) 

for example:

when name = h2o compound = ['', 'h2', 'o'] r = ['h', '2', 'o'] 

i want multiply 2 h making value "['h', 'h', 'o']."

tldr: want integers following names in list print listed object 'x' amount of times (e.g. [o, 2] => o o, [c, o, 2] => c o o)

the question complicated, let me know if can clarify it. thanks.

how following, after define compound:

test = re.findall('([a-za-z]+)(\d*)', compound) expand = [a*int(b) if len(b) > 0 else (a, b) in test] 

match on letters of 1 or more instances followed optional number of digits - if there's no digit return letters, if there digit duplicate letters appropriate value. doesn't quite return expected - instead return ['hh', 'o'] - please let me know if suits.

edit: assuming compounds use elements consisting of either single capital letter or single capital followed number of lowercase letters, can add following:

final = re.findall('[a-z][a-z]*', ''.join(expand)) 

which return elements each separate entry in list, e.g. ['h', 'h', 'o']

edit 2: assumption of previous edit, can reduce whole thing down couple of lines:

name = raw_input("insert name of molecule/atom find rmm/ram: ") test = re.findall('([a-z][a-z]*)(\d*)', name) final = re.findall('[a-z][a-z]*', ''.join([a*int(b) if len(b) > 0 else (a, b) in test]))