c - How to use arithmatic operations on uint64_t? -

i trying make program divides number given number , prints out remainder , solution of given number divided 10. code isnt printing out correct values. here following code:

#include <stdio.h> #include <string.h> #include <stdint.h> #include <stdlib.h> uint64_t divide(uint64_t,uint64_t);  int main(int argc, char *argv[]) {          uint64_t num1 = 224262;         uint64_t num2 = 244212;         divide(num1,num2);  }   uint64_t divide( uint64_t set1, uint64_t set2 ) {          printf("%lx\n",set1);         uint64_t remainder = set1%10;         printf("%lx\n",remainder);         set1= set1/10;         printf("%lx\n",set1); } 

currently output of gives me following

36c06 2 579a 

how have correctly outputs divided value , remainder?

assuming platform has long size 64 bits, correct format printfs %lu

uint64_t divide( uint64_t set1, uint64_t set2 ) {     printf("%lu\n",set1);     uint64_t remainder = set1%10;     printf("%lu\n",remainder);     set1= set1/10;     printf("%lu\n",set1);      return set1; } 

using predefined format specifier of inttypes.h can write

#include <stdio.h> #include <string.h> #include <stdint.h> #include <stdlib.h> #include <inttypes.h>  uint64_t divide(uint64_t,uint64_t);  int main(int argc, char *argv[]) {     uint64_t num1 = 224262;     uint64_t num2 = 244212;      divide(num1,num2); }   uint64_t divide( uint64_t set1, uint64_t set2 ) {     printf("%"priu64"\n",set1);     uint64_t remainder = set1%10;     printf("reminder = %"priu64"\n",remainder);     set1= set1/10;     printf("division = %"priu64"\n",set1);      return set1; }