python - numpy append to an indexed array (after np.where) -

i want append values selection of array without having go through loop.

i.e. if want add 0 values locations of array:

a=np.array([[1,2,3,4,5],[1,2,3,4,5]])     condition=np.where(a>2)     a[condition]=np.append(a[condition],np.array([0]*len(condition[0])))  -> valueerror: shape mismatch: value array of shape (12,) not broadcast indexing result of shape (6,) 

edit clarification:

i need add values (and dimension if needed) selected array location. loop looks that:

for t in range(len(ind)):     c = cols[t]     r = rows[t]     if data1[r, c] > 2:         data2[r,c]=np.append(data2[r,c],t) 

is there way remove loop (~100 000 iterations)? thank

let's @ pieces:

in [92]: a=np.array([[1,2,3,4,5],[1,2,3,4,5]])         ...: condition=np.where(a>2)       ...:  in [93]: out[93]:  array([[1, 2, 3, 4, 5],        [1, 2, 3, 4, 5]]) in [94]: condition out[94]:  (array([0, 0, 0, 1, 1, 1], dtype=int32),  array([2, 3, 4, 2, 3, 4], dtype=int32)) in [95]: a[condition] out[95]: array([3, 4, 5, 3, 4, 5]) in [96]: np.append(a[condition],np.array([0]*len(condition[0]))) out[96]: array([3, 4, 5, 3, 4, 5, 0, 0, 0, 0, 0, 0]) 

you trying put 12 values 6 slots. no can do!

what expecting? don't think should speculate. go ahead show loop.