regex - Escape special character ^ in a regular expression in Java -

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• what special characters must escaped in regular expressions? 8 answers

i want split string in java following format: "value^1" initial part, "value" in string.

i wanted use split instead of substring, tried this:

string.split("^")[0] 

but unfortunately ^ special character , guess has escaped. tried split("\^") no luck.

anybody knows how achieve using split?

thanks!

escape escape: split("\\^"). or split(pattern.quote("^")).

but since want first part of it, there's no need use split:

int pos = string.indexof('^'); string firstpart = (pos != -1) ? string.substring(0, pos) : string;