tsql - Xquery to find the value of an xml element -

all,i trying value of element value when value of name org_id.this xml placed in database external process don't have control over. there multiple parematervalue nodes ,so not sure position of value element when name org_id.the guarantee there 1 element name value org_id.

is there way find value of value in scenario?

sample xml(my_xml)

 <parametervalues>           <parametervalue>             <name>car_model</name>             <value>all</value>         </parametervalue>         <parametervalue>             <name>debug</name>             <value>0</value>         </parametervalue>         <parametervalue>             <name>org_id</name>             <value>123456</value>         </parametervalue>     </parametervalues>  xquery       select           my_xml.value('(/parametervalues/parametervalue/value)[3]','int') org_wk               #test_xml              my_xml.exist('/parametervalues/parametervalue/name[text() = "org_id"]') = 1 

this should trick:

-- sample data create table #test_xml (my_xml xml); insert #test_xml values ('<parametervalues>               <parametervalue>                 <name>car_model</name>                 <value>all</value>             </parametervalue>             <parametervalue>                 <name>debug</name>                 <value>0</value>             </parametervalue>             <parametervalue>                 <name>org_id</name>                 <value>123456</value>             </parametervalue>         </parametervalues>');  -- solution     select x2.p.value('(text())[1]', 'varchar(100)')  #test_xml x1 cross apply x1.my_xml.nodes('//parametervalue[name="org_id"]/value') x2(p);